one of the digits of a two digit number is twice the other digit. the sum of the original numbers amd the number formed by reversing the digits is 99. find the number
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let the original number be xy and as one of the digits of this two digit number is twice the other digit. let us assume x = 2y
given that xy + yx = 99
⇒ 10x + y + 10y + x = 99
⇒ 20y + y + 10y + 2y = 99
⇒ 33y = 99
⇒ y =3
⇒ x = 6
so the original number is 63 and the reverse is 36
⇒ 63 + 36 = 99
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