One of the end point of circle having center (2,−3) is (4,−1),then the other end point of
diameter lie on .........
(a) X-axis (b) Y-axis (c) I-quadrant (d) II-quadrant
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Answer: Let AB be a diameter of the circle having its centre at C(1, -3) such that the coordinates of one end A are (4, -1).
Let the coordinates of B be (x,y).
Since C is the mid-point of AB. Therefore,the coordinates of C are(
2
x+4
,
2
y−1
).
But, the coordinates of C are given to be (1,-3).
∴
2
x+4
=1and
2
y−1
=−3
⇒x+4=2andy−1=−6
⇒x=−2andy=−5
Hence,the coordinates of B are (-2, -5).
Step-by-step explanation: PLEASE MAKE ME THE BRAINLEIST
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