One of the end points of a circle having centre at origin is A(3, -2) then the other end
point of the diameter has coordinates
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Step-by-step explanation:
a) The equation of the circle centred at (x₀,y₀) and passing through (x₁,y₁) is (x-x₀)²+(y-y₀)² = (x₁-x₀)²+(y₁-y₀)². Here the centre is the origin, so this simplifies to x²+y² = x₁²+y₁².
b) The centre of the circle is the midpoint(M) of the diameter with one end at P. The other end is at 2M-P. Here M is the origin, so the other end is -P.
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