One of the equal sides is = 6 cm, vertex angle = 45 degrees . Measure the base angles.
Answers
Construct an isosceles ∆ABC such that:
(i) AB = AC = 6.5 cm and ∠A = 60°
(ii) One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
(iii) BC = AB = 5-8 cm and ZB = 30°. Measure ∠A and ∠C.
triangles
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1 Answer
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answered Jun 11, 2019 by priya12 (-12,638 points)
(i) Steps of Construction :

(i) Draw a line segment AB = 6.5 cm.
(ii) At A, draw a ray making an angle of 60°.
(iii) Cut off AC = 6.5 cm
(iv) JoinBC.
∆ABC is the required triangle.
(ii) Steps of Construction :
(i) Draw a line segment AB = 6 cm

(ii) At A, construct an angle equal to 45°
(iii) Cut off AC = 6 cm
(iv) Join BC.
∆ ABC is the required triangle.
On measuring, ∠B and ∠C, each is equal 1° to, 67°
(iii) Steps of Construction :
(i) Draw a line segment BC = 5.8 cm

(ii) At B, draw a ray making an angle of 30°.
(iii) Cut off BA = 5.8 cm
(iv) Join AC.
∆ ABC is the required triangle On measuring ∠C and ∠A, each is equal to 75°.
Answer:
67.5
Step-by-step explanation:
Since it is given one of the equal sides therefore there are two sides which are equal.So it will be an isosceles triangle.
lete ABC be the triangle.
angle A=45
angle B=angle C =?
A+B+C=180
B+C=180-45(ANGLE A =45)
2B=135
B=135/2=67.5
C=B=67.5