Question

one of the equal sides of an isosceles triangle is 18 cm and its perimeter is 48 cm. Find the area of the triangle​

Answer 1

Answer:

here,

suppose a= b=18

now, perimeter = a+b+c

or, 48 = 18 + 18 + c

or, c = 12

area of isosceles triangle = b/4( √4 a^2 - b^2)

= 12/4 (√4 * 18^2 - 12^2)

= 3(√1296-144)

= 3(√1152)

=3*33.94

= 101.82cm^2

i hope this is useful for you

Step-by-step explanation: