One of the equal sides of an issoscalen triangle is extent in the direction of vertex opposite to base .Prove exterior angle is double of the base angle
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given : AB=AC
To prove : ∠BAD=2∠B= 2∠C
proof:
In isoscales Δ ΑΒC
AB=AC
∠B=∠C=∠1
BAD=∠4
∠4=∠1+∠1[in any Δ the ext∠ is equal to the sum of its opposite interior ∠ s]
∠4 = 2∠1
∠BAD=2∠B=2∠C
To prove : ∠BAD=2∠B= 2∠C
proof:
In isoscales Δ ΑΒC
AB=AC
∠B=∠C=∠1
BAD=∠4
∠4=∠1+∠1[in any Δ the ext∠ is equal to the sum of its opposite interior ∠ s]
∠4 = 2∠1
∠BAD=2∠B=2∠C
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