One of the exterior and interior angles of a parallelogram are in ratio 2:3 . Find all angles of the parallelogram
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Answered by
2
Answer:
Let the //gm be ABCD.
Extend a line E from D.
Now,
angle BDC + angle BDE= 180 (linear pair)
given,
ratio= 2:3
therefore,
2x+3x=180
5x=180
x=36
Now,
angle BDC = 2x=2×36= 72
We know that,
Opposite angles of a //gm are equal.
So, angle D=angle A and angle C = angle B
since we have found angle D, angle A also equals 72.
Let angle B and angle C be x
x+x+72+72=360 ( property of //gm)
2x+144=360
2x=360-144
2x=216
x=216÷2
x=108
angle A= 72
angle B=108
angle C=72
angle D=108
*this can also be solved through interior alternate angles property*
Answered by
0
Answer:
A. T. Q
2x+3x=180
5x=180
=36
2*36=72
angle 1 =angle 3=72°
<1+<2=180°
<2=180-72
<2 = 108°
<2 =<4=108°
hence done
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