Question

one of the exterior angle of a ∆ABC measures 150° if one of the interior opposite angle is 75°. find the other interior opposite angle. what type of triangle is this ?

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Answer 1

Solution :-

☑ By exterior angles theorem

$150 = 75 + x \\ \\ 15 0 - 75 = x \\ \\ 75 = x$

☑Other angle is 75° !! ❤

Answer 2

Answer:

we know that,

Sum of the angles in a line is 180° it is linera pair.

Let the angle be x.

So, x+150°=180°

=>x=30°

Now, sum of the angles of the triangle is 180°

x+30°+75°=180 [ given 75° ]

=>x=180°-105°

=>x=75°

Here, two angles are equally

Therefore, it is isosceles triangle

Hope it will be helpful to you