One of the exterior angle of a triangle is 120⁰ and the interior opposite angle are in the
ratio 3:5. find the angles of the triangle .
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exterior angle = sum of opposite interior angles
120 = a + b
a/b = 3/5
a=3×b/5
120 = 3b/5 + b
120 = 8b/5
b = 120×5/8
b = 15×5
b= 75
a = 3×75/5
a = 45
c= 180-120
c = 60
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Answer:
given ratio is 3:5 3× + 5× =120° 8× =15 3× =3 (15) = 45...
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