One of the exterior angles of a triangle is 100 degrees and the interior opposite angles are in the ratio 2:3. Find all the angles of the triangle
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the exterior angle is 100°
so the rule was applied that , if a side of a triangle is produced the exterior angles so formed is equal to the sum of interior opposite angle
so 2:3
2x+3x=100
5x=100
x= 20
2x= 40
3x=60
third angle found by liner pairs
180=100-z
z =80
first :40
second:60
third:80
so the rule was applied that , if a side of a triangle is produced the exterior angles so formed is equal to the sum of interior opposite angle
so 2:3
2x+3x=100
5x=100
x= 20
2x= 40
3x=60
third angle found by liner pairs
180=100-z
z =80
first :40
second:60
third:80
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