Question

One of the exterior angles of a triangle is 100° and the interior opposite angles are in a ratio of 2:3. Find all the angles of the triangle. ​

Answer 1

angle ACD =100°

let angle A = 2x and angle B =3x

angle ACB = 180°- ACD =180 -100 =80° (linear pair)

angle A+Angle B + angle C =180°

2x+3x+80° =180

5x =100°

x= 20 °

So, angle A= 2x= 40°

angle B=3x=60°

angle C =80°