One of the exterior angles of a triangle is 110° nd the interior opposite angles are in the ratio 6:5.find the angle of a triangle
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A = 110 deg
B / C = 6 / 5 => 5 B = 6 C
B + C = B + 5/6 * B = 11/6 * B
A + B + C = 180
110 + B + 11/6 * B = 180
B = 6 * 70 / 17 = 24.6 deg
C = 180 - 110 - 24.6 = 45.4 deg
B / C = 6 / 5 => 5 B = 6 C
B + C = B + 5/6 * B = 11/6 * B
A + B + C = 180
110 + B + 11/6 * B = 180
B = 6 * 70 / 17 = 24.6 deg
C = 180 - 110 - 24.6 = 45.4 deg
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