Question

One of the exterior angles of a triangle is 112° and the corresponding interior opposite angles are in the ratio 3:4.Find the angles​

Answer 1

Answer:

Let a ∆ABC

Let the exterior angle C = 112 °

Now interior angle C= 68°

Sum of three angles of ∆ =180°_________(i)

Now , angle A: angle B= 3:4

So let angle A=3x

angle B= 4x

Now using (i)

3x + 4x + 68°= 180°

7x+ 68°= 180°

7x= 112°

x= 16

Now angles are A= 48°

B=64°

C=68°~

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