one of the exterior angles of a triangle is 130 and the interior opposite angle are in the ratio 2 ratio 3. Find the angles of the triangle
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Let interior Angle be 2x and 3x
ATQ,
2x+3x=130. (exterior Angle sum property of ∆)
5x = 130
X = 130/5 = 26
2x = 52°
3x = 78°
And other angle of∆ is 180-130 = 50°
ATQ,
2x+3x=130. (exterior Angle sum property of ∆)
5x = 130
X = 130/5 = 26
2x = 52°
3x = 78°
And other angle of∆ is 180-130 = 50°
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deepika4236:
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