Question

One of the exterior angles of triangle is 100 degree. The interior opposite angles are equal to each other. Find the measure of these equal interior opposite angles.

Answer 1

the interior opp angles are 50 degree

Answer 2

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{AnswEr:-}}}$

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• The measure of these equal interior opposite angles = 50°

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$\sf{\underline{\green{Given:-}}}$

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• One of the exterior angles of triangle is 100°. The interior opposite angles are equal to each other.

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$\sf{\underline{\green{Find:-}}}$

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• The measure of these equal interior opposite angles = ?

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$\sf{\underline{\green{Explanation:-}}}$

Let $\angle$A = $\angle$B = x

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$\sf{\underline\pink{A.T.Q:-}}$

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$\longrightarrow \sf {\angle ACD = \angle A + \angle B}$

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$\longrightarrow \sf {100\degree = x + x }$

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$\longrightarrow \sf {100\degree = 2x}$

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$\longrightarrow \sf {x = \cancel\dfrac{100\degree}{2} }$

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$\longrightarrow{\underline{\boxed{\sf{x = 50\degree}}}}$

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$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

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• The measure of these equal interior opposite angles is 50°.

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$\rule{200}{2}$