Question

One of the factor(1+ 7x^2) +49x^2 -1)

Answer 1

Given:

The polynomial (1 + 7x^2) + 49x^2 - 1)

To find:

One of the factor (1 + 7x^2) + 49x^2 - 1)

Solution:

From given, we have,

(1 + 7x^2) + 49x^2 - 1)

In order to find the factor of a given polynomial, we need to equate the polynomial to zero.

So, we get,

(1 + 7x^2) + 49x^2 - 1) = 0

1 + 56x^2 - 1 = 0

56x^2 = 0

x^2 = 0  

x = 0

Therefore, the factor of (1+ 7x^2) +49x^2 -1) is 0.

Answer 2

Answer:

One of the factor(1+ 7x^2) +49x^2 -1)