One of the factor for x3-23x2+142x-120 is
Answers
Answered by
6
Let p (x) = x³ - 23 x² + 142 x - 120
x = 1
p (1) = 1³ - 23 (1)² + 142 (1) - 120
= 1 - 23 + 142 - 120
= 143 - 143
= 0
x = 1
p (1) = 1³ - 23 (1)² + 142 (1) - 120
= 1 - 23 + 142 - 120
= 143 - 143
= 0
Answered by
3
hope this solution helps you
Attachments:
Similar questions