Question

one of the factor of 1-64a^3..


answer with steps ....

answer on paper

Answer 1

hope it helps you my friend☺☺☺

Answer 2

Answer:

$\huge\blue{\mid{\fbox{\tt{Solution:-}}\mid}}$

$1 - {64a}^{3}$

$= {(1)}^{3} + {( - 4a)}^{3} + 3(1)( - 4a)(1 - 4a)$

$=1 - {64a}^{3} - 12a(1 - 4a)$

$=1 - {64a}^{3} - 12a + {48a}^{2}$

$\small\red{\mid{\fbox{\tt{Hope it's helpful uh ♡♡}}\mid}}$