Question

One of the factor of 1/6a² – a + 4/3 is​

Answer 1

$\huge\bf{Answer:-}$

Given:-

$\dfrac{1}{6}a² -a + \dfrac{4}{3} = 0$

To Find :-

The Factors of $\dfrac{1}{6}a² -a + \dfrac{4}{3} = 0$

$\huge\bf{Solution:-}$

$\dfrac{1}{6}a² -a + \dfrac{4}{3} = 0$

• By doing the LCM of 3 and 6 we get 6

$\dfrac{a² - 6a + 8}{6} = 0$

a² - 6a + 8 = 0

• By doing Middle Term Factor , we get

a² - ( 4 +2 )a + 8 = 0

a² - 4a - 2a + 8 = 0

• By taking common

a ( a - 4 ) -2 ( a - 4) = 0

(a - 4 ) ( a -2 ) = 0

Therefore , the factors are :

( a - 4 ) = 0

a = 4

and

( a - 2 ) = 0

a = 2