Question

one of the factor of (25x square-1)+(1+5x square ) is ques no.3

Answer 1

(25x²-1)+(1+5x)²
=[(5x)²-(1)²]+[1+5x]²
=(5x-1)(5x+1)+(1+5x)(1+5x)
take 1+5x common
=(1+5x)[(5x-1)+(5x+1)]
=(1+5x)(5x-1+5x+1)
=(1+5x)(10x).

so, factors of given eq are 10x & 1+5x.

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Thankuu

Answer 2

Given that,

The equation is

$(25x^2-1)+(1+5x)^2$

We need to calculate the one factor of this equation

Using given equation

$(25x^2-1)+(1+5x)^2$

We can write in form of $a^-b^2$

So,

$((5x)^2-1^2)+(1+5x)^2$

We know that,

$a^2-b^2=(a+b)(a-b)$

Now, on comparing

$(5x+1)(5x-1)+(1+5x^2)$

$(5x+1)(5x-1+1+5x)$

$(5x+1)(10x)$

So, one factor is 10x and another factor is (5x+1)

Hence, one of the factor is 10x.