Math, asked by sitaramguru22, 1 year ago

One of the factor of 2a raise 7 - 128a


QGP: Is it (2a)^7 - 128a ?

Answers

Answered by biplov
28
Given,

2a^7-128a

Calculation,

=2a^7-128a

=2a×(a^6-64)

Using a²-b²=(a+b)(a-b)

=2a × (a^2×3-8²)

Using a^(mn)=(a^n)^m

=2a×[(a³)²-8²)]

Using a²-b²=(a+b)(a-b)

=2a ×(a³-8)×(a³+8)

=2a×(a³-2³)(a³+2³)

Using a³-b³=(a-b)(a²+ab+b²)

=2a×(a-2)×(a²+a×2+2²)×(a+2)×(a²-a×2+2²)

=2a×(a-2)×(a²+2a+4)×(a+2)×(a²-2a+4)

Answer=>2a×(a-2)×(a²+2a+4)×(a+2)×(a²-2a+4)

Hope it helps
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Answered by DEEPASVI
3

Step-by-step explanation:

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