Math, asked by sahil154, 1 year ago

one of the factor of (a2-b2)(c2-d2)-4abcd is

Answers

Answered by parisakura98pari
146
(a² - b²)(c² - d²) - 4abcd = a²c² - a²d² - b²c² + b²d² - 2abcd - 2abcd

=a²c² + b²d² - 2abcd - { a²d² + b²c² - 2abcd } = (ac-bd)² - (ad- bc)²

= (ac-bd - ad + bc) (ac -bd + ad -bc)           [ p² - q² = (p-q)(p+q) ]

Hope this helps.



parisakura98pari: You can factorise it further
parisakura98pari: (ac - bd - ad + bc) (ac - bd + ad - bc) = (a+b)(c-d)(a-b)(c+d)
Answered by sofiya275
22

Step-by-step explanation:

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