Math, asked by beautiful66, 1 year ago

one of the factor of x^2 -x-12....

answer with steps..

answer on paper..

answer is x-4

Answers

Answered by ayushchoubey
3
your answer is
 {x}^{2}  - x - 12 \\  {x}^{2}  - 4x + 3x - 12 \\ x(x - 4) + 3(x - 4) \\( x + 3)(x - 4) = 0 \\ x + 3 = 0 \\ x =  - 3 \: is \: does \: not \: exist \\ x - 4 = 0 \\ x = 4 \:  \: ans
Answered by siddhartharao77
3
The answer is attached below.


Hope it helps!
Attachments:

beautiful66: your hand writing is good
siddhartharao77: Thank you :-)
beautiful66: please answer this. .....a^4+5a^3+6a^2
siddhartharao77: Sorry for the late reply.
siddhartharao77: a^4 + 5a^3 + 6a^2

= > a^2(a^2 + 5a + 6)

= > a^2(a^2 + 2a + 3a + 6)

= > a^2(a(a + 2) + 3(a + 2))

= > a^2(a + 3)(a + 2)
beautiful66: thanks
siddhartharao77: Welcome!
beautiful66: please answer my question
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