Question

One of the factor of x2 – 121 is​

Answer 1

Step-by-step explanation:

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=x and b=11 .

(x+11) is one of the factor.

(x-11) is another factor.

Answer 2

Answer:

x^2 - 121

using identity a^2 - b^2 = (a+b) (a-b)

(x)^2 - (11)^2

(x + 11 )( x- 11)

Factors of x^2 - 121 = (x+ 11 ) and (x- 11)

ADDTIONAL INFORMATION

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• This is degree 2 polynomial which means it has two zeros.

• A factor of a polynomial is that through which when the whole polynomial is divided , the remainder is zero.

• Zero of this polynomial is 11 , (-11)