One of the factors of (1 + 3y)² + (9y² – 1) is
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6y(3y+1)
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(1+3y)²+ (9y²-1)=
(1+3y)²+ (3y+1)(3y-1)=
(3y+1)(3y+1+3y-1)=
(3y+1)6y= 6y(3y+1)
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