Question

One of the factors of (1+3y)square +(9ysquare-1) is

Answer 1

Answer:

Factors are 3, 2 , y and 3y+1

Step-by-step explanation:

First expand (1+3y)². We know,(a+b)² = a²+2ab+b²

So, using this formula we expand the equation.

The equation is (1+3y)²+(9y² - 1)

= [1² +2(1) (3y) + (3y)²] + 9y² - 1

= [1 + 6y +9y²] + 9y²-1

= 9y²+6y+1+9y²-1

= 18y² + 6y

Now take 6y as common--

= 6y (3y+1)

So factors are 6y and 3y+1

6y can be written as 2*3*y

So, factors are 2,3, y and 3y+1

Hope this helps mate!

There is another process to solve this, but it is a confusing one. This process I said now is an easy one.

Hope you understood!

Thank You