Question

One of the factors of (1+7x)^2+(49x^2-1) is...

Answer 1

Step-by-step explanation:

$= {(1 + 7x)}^{2} + (49 {x}^{2} - 1) \\ = {(1 + 7x)}^{2} + (( {7x)}^{2} - {(1)}^{2} ) \\ = {(1 + 7x)}^{2} + (7x + 1)(7x - 1) \\ = (1 + 7x)(1 + 7x + 7x - 1) \\ = 14x(7x + 1) \\ \\ hope \: it \: will \: help \: you$

Answer 2

Answer:

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Given:

(1+7x)² + (49x²-1)

To find:

Factor of the (1+7x)² + (49x²-1).

Solution:

1) To find the factor of the (1+7x)² + (49x²-1) we will solve the terms individually.

2) (1+7x)² + (49x²-1)

(1+7x)² + (7x+1)(7x-1)   { By the Identity A²-B²= (A+B)(A-B) }

(7x+1)(1+7x+7x-1)   { taking out the common terms}

(7x+1)(14x)

3) The factors of the (1+7x)² + (49x²-1) are 7x+1 and 14x.

(7x+1) and 14x are factors.