Question

one of the factors of (1+8x)2+(49x²-1​

Answer 1

Answer:

Step-by-step explanation:

\begin{gathered}= {(1 + 7x)}^{2} + (49 {x}^{2} - 1) \\ = {(1 + 7x)}^{2} + (( {7x)}^{2} - {(1)}^{2} ) \\ = {(1 + 7x)}^{2} + (7x + 1)(7x - 1) \\ = (1 + 7x)(1 + 7x + 7x - 1) \\ = 14x(7x + 1) \\ \\ hope \: it \: will \: help \: you\end{gathered}=(1+7x)2+(49x2−1)=(1+7x)2+((7x)2−(1)2)=(1+7x)2+(7x+1)(7x−1)=(1+7x)(1+7x+7x−1)=14x(7x+1)hopeitwillhelpyou

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given expression is (1+8x)²+(49x²-1)

=>1²+2(1)(8x)+(8x)²+49x²-1

since (a+b)²=a²+2ab+b²

=>1+16x+64x²+49x²-1

=>16x+113x²

=>x(16+113x)

=>x(113x+16)

The factors are 'x' and '(113x+16)'