Question

One of the factors of 49x²-1 is:​

Answer 1

Answer:1) To find the factor of the (1+7x)² + (49x²-1) we will solve the terms individually.

2) (1+7x)² + (49x²-1)

(1+7x)² + (7x+1)(7x-1)   { By the Identity A²-B²= (A+B)(A-B) }

(7x+1)(1+7x+7x-1)   { taking out the common terms}

(7x+1)(14x)

3) The factors of the (1+7x)² + (49x²-1) are 7x+1 and 14x.

(7x+1) and 14x are factors.

Step-by-step explanation:

Answer 2

$49 {x}^{2} - 1 = 0 \\ {x}^{2} = \frac{1}{49 } \\ x = \frac{1}{7} \: and \: - \frac{1}{7}$

(x - 1/7) and ( x + 1/7) are the two factors

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Hope this helps to you...!!