Question

one of the factors of a^3-b^3-a^2b+ab^2+a^2-b^2 is​

Answer 1

Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2−ab+b2)a3+b3=(a+b)(a2-ab+b2) where a=aa=a and b=bb=b. Factor 3ab3ab out of 3a2b+3ab23a2b+3ab2.

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