Question

one of the fraction of x²+1/x²+2-2×-2/ x is​

Answer 1

Step-by-step explanation:

x

2

+2x

1

=

x(x+2)

1

x(x+2)

1

=

x

A

+

x+2

B

... eqn.1

x(x+2)

1

=

x(x+2)

A(x+2)+Bx

1=Ax+2A+Bx

On comparing coefficients of x and constant term, we get

2A=1andA+B=0

∴A=

2

1

andB=

2

−1

Put values of A and B in eqn.1

x(x+2)

1

=

2x

1

−

2(x+2)

1

=

2

1

[

x

1

−

x+2

1

]