One of the kettle transfers 2000 J of energy every second.
1640 J of this energy is stored in the hot water inside the kettle.
360 J of this energy is wasted energy.
Can you calculate the efficiency of this kettle?
Answers
Answered by
0
Answer:
280
hope it's useful
this is the answer
Answered by
0
Answer:
0.82
Explanation:
Efficiency = useful power out ÷ total power in
1640 J ÷ 2000 J = 0.82
Hope it will helpful for your work or something
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