Question

one of the largest domes ever built in the
world.
i) Find the surface area of the cubical portion of the Gumbaz excluding the
top and bottom if one side is about 47 m.​

Answer 1

Answer:

Surface area of a cube =6a^2

but,given that exclude the top and bottom,in that case ,area of 4 walls =4a^2

since, a=47m,

therefore area of 4 walls,=

4×a×a

4×47×47=8836m^2 ANS

Answer 2

Answer:

the following questions regarding the case study box of gol gambaz bijapur

and the given data is that the gol gambaz  is a cubical portion of side 47m

Step-by-step explanation:

1Q) find the surface area of the cubical portion incuding the top and the bottom and the side is 47m ?

A. given,

   side=47m

    so we need to find the surface area of the cubical portion means

we need to find the C.S.A of the cube = 4a^2

                                                           =4(47)^2

                                                           =4(2209) = 8836m^2

2Q) find the volume of the cubical portion ?

A. given,

 side=47m

 so, we need to find the volume of the cubical portion

so the volume of the cube is = a^3

                                             = (47)^3

                                              = 103823 cu.m