Question

one of the parallel side of a Trapezium is thrice the other the area of the trapezium is 440 CM square and its height is 22 cm find the length of its two parallel sides​

Answer 1

Answer:

Let the parallel sides be x and 3x

Area of trapezium = 1/2 h(b1 + b2)

440 = 1/2 (22) (x + 3x)

440 = 11 (4x)

440 = 44x

x = 440/44

x = 10

First parallel side = x = 10 cm

Second parallel side = 3x = 30 cm

Pls follow.....

Answer 2

$\huge{\underline{\underline{\sf{\red{SOLUTION:-}}}}}$

$\sf{\underline{\green{Answer-}}}$

• $\sf \: Length \: of \: first \: side= \: 10cm$

• $\sf \: Length \: of \: second\: side= \: 30cm$

$\sf{\underline{\green{Given-}}}$

• One of the parallel side of a Trapezium is thrice the other the area of the trapezium is 440 CM² and its height is 22 cm.

$\sf{\underline{\green{We\:Have\:To\:Find-}}}$

• The length of its two parallel sides.

$\sf{\underline{\green{Explanation-}}}$

$\sf \: Let \: the \: first \: side \: be=x$

$\sf \: Let \: the \: Second \: side \: be= \: 3x$

$\sf \: (Given) -\: Height= \: 22cm$

$\sf\underline{\red{Formula\:used\: here-}}$

$\bigstar \: \boxed{\sf {Area \: of \: trapezium \: = \: \frac{1}{2} (a+b) \times h}}$

➨⠀$\sf440 = \frac{1}{2} (x + 3x) \times 22$

➨⠀$\sf440 = (x + 3x) \times 11$

➨⠀$\sf \: 440 = 4x \times 11$

➨⠀$\sf \: x = {\dfrac{\cancel{440}}{\cancel{44}}\:}$

➨⠀${\sf { x= 10}}$

$\sf\underline\red {\: Now \: putting \: the \: values-}$

➨⠀⠀$\boxed{\sf { First\: side= 10 \times 1 = 10cm}}$

➨⠀⠀$\boxed{\sf {Second\: side= 10 \times 3 = 30cm}}$