Question

One of the parallel sides of a trapezium is 10 cm and altitude of a trapezium is 5cm . If its area is 40sqcm. Find the length of other parallel side.

Answer 1

let the other parallel be x
then a/q
area=1/2*(a+b)h
40=1/2(10+x)5
10+x=40*2/5
10+x=16
x=16-10
x= 6

Answer 2

let the other parallel side of trapezium be x.

The area of trapezium is given by -

1/2 × (sum of parallel sides) × altitude

The area of trapezium is 40cm².

Hence,

$40 \: = \frac{1}{2} \times (10 + x) \times 5 \\ or \: 80 = (10 + x) \times 5 \\ or \: 80 = 50 + 5x \\ or \: 30 = 5x \\ or \: x = 6 \: cm$
Answer : The other parallel side of the trapezium is 6cm.