Question

One of the parallel sides of a trapezium is 8 cm less than the other. If distance between the parallel sides is 10 cm and area of trapezium is 200 cm”, find the
length of each parallel sides.​

Answer 1

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Answer 2

let ABCD be the trapezium such that AB is parallel to CD.

AB=CD-8

area of trapezium ABCD=(1/2)×(AB+CD)×h

200cm²=(1/2)×(2CD-8)×10

5×(2CD-8)=200

2CD-8=40

2CD=48

CD=24cm

AB=24-8

AB=16cm

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