Question

One of the parallel sides of a trapezium is 8 cm less
than the other. If distance between the parallel sides
is 10 cm and area of trapezium is 200 cm?, find the
length of each parallel side.​

Answer 1

Answer:

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Step-by-step explanation:

Let the length of the parallel side be x

The other parallel side is x + 8

Given the area = 312 cm² and the height = 24 cm

Solve x:

area = 1/2 (a + b) (h)

312 = 1/2 ( x + (x + 8) ) (24)

312 = 12( 2x + 8)

2x + 8 = 26

2x = 18

x = 9 cm

Find the length of the parallel sides:

one side = x = 9 cm

the other side = x + 8 = 9 + 8 = 17 cm

Answer 2

Answer:

The length of the parallel sides is 16cm and 24cm

Explanation:

Given

• The given shape is a trapezium
• One || side is 8cm less than the other.
• Distance between parallel sides is 10 cm.
• Area of the trapezium = 200cm²

To Find

• Length of the parallel sides.

Solution

Let one parallel side = x

Other parallel side = x + 8

Distance between the parallel sides is the height of the trapezium.

Area of a trapezium = 1/2 × height × ( sum of parallel sides )

⟹ 200cm² = 1/2 × 10cm × { ( x + 8cm ) + x}

⟹ 200cm² = 5cm( 2x + 8cm)

⟹ 200cm²/5cm = 2x + 8cm

⟹ 40cm = 2x + 8cm

⟹ 40cm - 8cm = 2x

⟹ 32cm = 2x

⟹ 32cm/2 = x

⟹ 16cm = x

One parallel side = x = 16cm

Other parallel side :

⟹ ( x + 8cm )

⟹ 16cm + 8cm

⟹ 24cm