one of the parallel sides of a Trapezium is twice the other if the distance between them is 5 cm and the area of 45 CM square find the parallel sides
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57
Area of a trapezium = 1/2×height (sum of parallel sides
given:the other parallel side is double the other. height is5cm.Area is 45 cm square.
let the parallel sides be x and 2x
1/2×5 (x+2x)=45
5 (x+2x)=45×2
5x+10x=90
15x=90
x=90/15
x=6
2x=12
so the parallel sides are 6cm and 12cm.
hope it helps and please mark brainliest
given:the other parallel side is double the other. height is5cm.Area is 45 cm square.
let the parallel sides be x and 2x
1/2×5 (x+2x)=45
5 (x+2x)=45×2
5x+10x=90
15x=90
x=90/15
x=6
2x=12
so the parallel sides are 6cm and 12cm.
hope it helps and please mark brainliest
prabh9378:
kiya
Answered by
19
Parallel side 1. =x cm(ps1)
Parallel side 2.=2x cm( PS 2)
Height of Trapezium = 5cm
Area of Trapezium = 45 cm
area of trapezium = 1/2(Ps1 + PS2)* h
45=1/2(x+2x)*5
45*2/5=3x
18=3x
x=6
2x=12
Mark me as a brain lest answer me.
Parallel side 2.=2x cm( PS 2)
Height of Trapezium = 5cm
Area of Trapezium = 45 cm
area of trapezium = 1/2(Ps1 + PS2)* h
45=1/2(x+2x)*5
45*2/5=3x
18=3x
x=6
2x=12
Mark me as a brain lest answer me.
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