one of the parallel sides of trapezoid is 2m longer than the other.The breadth is 1.5m and the area is6msq.find the sum of the lenghts.
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Area of trapezim=(1/2)h[sum of parallel sides]
h=height or breadth
let one parallel side be 'x'
other parallel side is 'x+2'
given,h=1.5
area of trapezium is 6
hence,
6=(1/2)(1.5)[x+x+2]
6=(1/2)(1.5)[2x+2]
x=3
hence sum of parallel sides is
x+(x+2)=3+(3+2)=8
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Answer:
8m
Step-by-step explanation:
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