Question

one of the perpendicular sides of a right angled triangle has 4cm more than twice of other side. It has area 80 cm square. find out lenghts of perpendicular side​

Answer 1

Answer:

Step-by-step explanation:

Let perpendicular side be x cm.

It othe side = 2x × 4.

So,

80=2x×4

2x=20

x=10 cm.

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Answer 2

Answer:

$x(x + 2) = 80 \\ {x}^{2} + 2x - 80 = 0 \\ x = \frac{ - 2 + - \sqrt{4 + 4(80)} }{2} \\ x = - 1 + - \sqrt{81} \\ x = - 1 + - 9 \\ x = 8 \: or \: - 10 \\ but \: length \: is \: not \: - ve \\ sides \: are \: \: 8 \: and \: 20\: and \:4 \sqrt{29}$

Step-by-step explanation:

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