Math, asked by rkumar07068, 7 months ago

one of the polynomials value at x= 1 is 1. find it .
a) 4x2-3x+7 b) 4x2+3x+7 C) 3x2+5x+7 d) 3x2+5X-7​

Answers

Answered by punamdevi098987
3

Mark as brainliest

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Attachments:
Answered by afiyaarifa208
0

Answer:

The division algorithm states that Dividend=Divisor×Quotient+Remainder that is f(x)=g(x)⋅q(x)+r(x)

Here, it is given that the dividend is f(x)=2x

4

−5x

3

+x

2

+3x−2, the divisor is 2x

2

−5x+3 and the remainder is −2x+1, therefore, by applying division algorithm we have:

2x

4

−5x

3

+x

2

+3x−2=(2x

2

−5x+3)g(x)+(−2x+1)

⇒2x

4

−5x

3

+x

2

+3x−2−(−2x+1)=(2x

2

−5x+3)g(x)

⇒2x

4

−5x

3

+x

2

+3x−2+2x−1=(2x

2

−5x+3)g(x)

⇒2x

4

−5x

3

+x

2

+5x−3=(2x

2

−5x+3)g(x)

⇒g(x)=

2x

2

−5x+3

2x

4

−5x

3

+x

2

+5x−3

Let us now divide 2x

4

−5x

3

+x

2

+5x−3 by 2x

2

−5x+3 as shown in the above image:

From the division, we observe that the quotient is x

2

−1 and the remainder is 0.

Hence, the quotient q(x)=x

2

−1.

solution

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