Question

One of the postulates of Bohr's atomic model is that angular momentum of a moving electron is quantized. Explain its meaning and calculate the angular momentum of third orbit(i.e.n=3)?​

Answer 1

Explanation:

Bohr never assumed stable electronic orbits with the electronic angular momentum quantized as l=mvr= nh/2π

Quantization of angular momentum means that the radius of the orbit and the energy will be quantized as well. Bohr assumed that the discrete lines seen in the spectrum of the hydrogen atom were due to transitions of an electron from one allowed orbit/energy to another.

Answer 2

Answer:

Bohr never considered that stable electronic orbits with electronic angular momentum quantized as l=mvr=nh/2 would exist.

(where v is the velocity, n is the orbit in which the electron is, m is the mass of the electron, and r is the radius of the nth orbit).

As angular momentum becomes quantized, the orbit's radius and energy become quantized as well. Bohr believed that transitions of an electron from one permitted orbit/energy to another were the cause of the definite lines visible in the spectrum of the hydrogen atom.

The angular orbit with n=3

Angular momentum of an electron in the n Bohr orbit of hydrogen atom L=$\frac{nh}{2Pie}$

For n=3

$L=\frac{3h}{2pie}$

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