one of the rectangle components of a force of 40 N is 20N . find the angle it makes with their components
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40² = 20² + x²
x²= 1200
x = 20√3
Tanα = 20/(20√3) = 1/√3
α = 30°
Tanβ = 20√3/20 = √3
β = 60°
Angles are 30° and 60°
x²= 1200
x = 20√3
Tanα = 20/(20√3) = 1/√3
α = 30°
Tanβ = 20√3/20 = √3
β = 60°
Angles are 30° and 60°
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