Question

One of the rectangular components of a velocity of 20 ms is 10ms. find other component

Answer 1

given velocity v = 20 m/s

let the given rectangular component is

cos somponent, so 10 = v cos x

so, other component will be sin component

i.e., v sin x

or, 10 = 20 cos x

or, cos x = 1/2

and as sin^2 x + cos^2 x = 1

or, 1 - cos^2 x = sin^2 x

or, 1 - (1/2)^2 = sin^2 x

so, sin x = sqrt( 1 - 1/4)

or, sin x = sqrt(3/4)

so, rectangular component is

20 sin x = 20 sqrt(3/4)

= 10 sqrt3

= 17.32 m/s

Answer 2

Answer:

Other component magnitude Q =$10\sqrt{3} ms^{-1}$

Explanation:

To Find :  Magnitude of Q bar ..

Rectangular components of a velocity of Magnitude (R)= $20ms^{-1}$

Rectangular components of a velocity of  Magnitude (P) =$10ms^{-1}$

The angle between the P bar and Q bar will be 90°

Let from the triangle ABC

                        $R^{2} =P^{2}+ Q^{2} \\R=\sqrt{P^{2}+Q^{2} } \\Q=\sqrt{R^{2}-P^{2} } \\Q=\sqrt{(20)^{2}-(10)^{2} } \\Q=\sqrt{3(100)} \\Q=10\sqrt{3} ms^{-1}$

Other component magnitude Q =$10\sqrt{3} ms^{-1}$

The project code is #SPJ2