one of the root of equation x^2+mx-5 is=2 m=??????????????
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x=2
x^2+mx-5=0
2^2+2m-5=0
4+2m-5=0
2m=1
m=1/2
Hope it helped you
x^2+mx-5=0
2^2+2m-5=0
4+2m-5=0
2m=1
m=1/2
Hope it helped you
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