one of the root of quadratic equation 2x+kx-2=0 is -2 find k
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Answered by
18
let f(x)=2x-kx-2,
since -2 is a root of quadratic equation.
then
f(-2)=0,
2×-2-k×-2-2=0,
-4+2k-2=0,
2k=4+2,
2k=6,
k=3
since -2 is a root of quadratic equation.
then
f(-2)=0,
2×-2-k×-2-2=0,
-4+2k-2=0,
2k=4+2,
2k=6,
k=3
Answered by
26
Hey dear friend,
Quadratic Equation=2x²+kx-2=0
Root of Equation= -2
Substituting x= -2 in equation
2*(-2)²+k*(-2)-2=0
2*4-2k-2=0
8-2k-2=0
6-2k=0
6=2k
k=3
perfectly fine pure correct answer
hope it helps you mark me as brainliest and follow me
Quadratic Equation=2x²+kx-2=0
Root of Equation= -2
Substituting x= -2 in equation
2*(-2)²+k*(-2)-2=0
2*4-2k-2=0
8-2k-2=0
6-2k=0
6=2k
k=3
perfectly fine pure correct answer
hope it helps you mark me as brainliest and follow me
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