Question

one of the roots of a quadratic equation is 4 minus root 7 find the equation ​

Answer 1

Answer:

$\alpha = 4 - \sqrt{7} \\ \alpha + \sqrt{7} = 4$

after compare

$\alpha + \beta$

$\beta = \sqrt{7}$

the equation is

${x}^{2} - ( \alpha + \beta )x - \alpha \beta \\ = {x }^{2} - (4 - \sqrt{7} + \sqrt{7} )x + (4 - \sqrt{7} ) \sqrt{7} \\ = {x}^{2} - 4x + 4 \sqrt{7} - 7$