One of the roots of equation 5m²+2m+k=0 is −7/5. Complete the following activity to find the value of ’k’.
Answers
Answered by
247
GIVEN :
5m²+2m+k=0
Here, k is unknown. Since, m = -7/5 is one root of the equation,so it will satisfy the equation..
On Putting m = -7/5 in GIVEN equation,
5m²+2m+k=0
5(-7/5)² + 2(-7/5) + k = 0
5 × (49/25) -14/5 + k = 0
49/5 -14/5 + k = 0
35/5 + k = 0
k = -35/5= -7
k = -7.
Hence,the value of k is -7.
HOPE THIS WILL HELP YOU...
5m²+2m+k=0
Here, k is unknown. Since, m = -7/5 is one root of the equation,so it will satisfy the equation..
On Putting m = -7/5 in GIVEN equation,
5m²+2m+k=0
5(-7/5)² + 2(-7/5) + k = 0
5 × (49/25) -14/5 + k = 0
49/5 -14/5 + k = 0
35/5 + k = 0
k = -35/5= -7
k = -7.
Hence,the value of k is -7.
HOPE THIS WILL HELP YOU...
Answered by
81
here , GIVEN:- one of the roots of the quadratic equation 5m² + 2m + k = 0
where, one of the zeroes is m = -7/5
now let us put the value of m in the equation for finding the value of k.
5m² + 2m + k = 0
5(-7/5)² + 2(-7/5) + k = 0
5*(49)/25 - 14/5 + k = 0
49/5 - 14/5 + k = 0
(49 - 14)/5 + k = 0
35/5 + k = 0
k = -35/5 = -7
hence,the value of k = -7
where, one of the zeroes is m = -7/5
now let us put the value of m in the equation for finding the value of k.
5m² + 2m + k = 0
5(-7/5)² + 2(-7/5) + k = 0
5*(49)/25 - 14/5 + k = 0
49/5 - 14/5 + k = 0
(49 - 14)/5 + k = 0
35/5 + k = 0
k = -35/5 = -7
hence,the value of k = -7
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