Question

One of the roots of equation kx²+2x-3=0,find the value of k​

Answer 1

Answer:

kx²+2x-3=0

as the root of the given equation is D=0

a=k,b=2,C=3

D=b²-4ac

O=2²-4(3k)

0=4-12k

12k=4

k=1/3

so the value is 1/3

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