Question

one of the roots of equation
${x}^{2} + mx - 5 = 0$
is 2 ; find m.


(1) -2


(2)
$- \frac{1}{2}$
(3)
$\frac{1}{2}$
(4) 2​

Answer 1

${x}^{2} + mx - 5 = 0 \\ root \: is \: 2 \\ {2}^{2} + 2m - 5 = 0 \\ 4 - 5 + 2m = 0 \\ 2m - 1 = 0 \\ 2m = 1 \\ m = \frac{1}{2}$

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